Math homework help!!!!!!!!?

Karl Jantzen: one million) four.nine + four/17 = four.ninety + zero.23 = five.thirteen two) one million/two + one million/two = two/two = one million three) four/nine + one million/three = four/nine + three/nine = 7/nine = zero.seventy seven four) one million/two - four/17 = nine/34 17/34 - eight/34 = nine/34 nine/34 = nine/34 ==> CORRECT five) five/6 - five/17 = zero.eighty three - zero.29 = zero.fifty four 6) one million/two - three/eleven = five.five/eleven - three/eleven = two.five/eleven = zero.227 7) five/7 - three/thirteen = zero.seventy one - zero.23 = zero.forty eight eight) one million/two x three/thirteen = three/26 (one million x three) / (two x thirteen) = three/26 three / 26 = three/26 ==> CORRECT nine) one million/two x four/eleven = (one million x four) / (two x eleven) = four / 22 = two/eleven 10) four/7 x five/19 = (four x five) / (7 x 19) = 20 / forty five = four/nine eleven) one million/two x five/12 = (one million x five) / (two x 12) = five / 24 12) ! five/eight / (five/thirteen) = one million five/eight five/eight x thirteen/five = one million + five/eight (five x thirteen) / (eight x five) = eight/eight + five/eight sixty five / forty = thirteen/eight thirteen / eight = thirteen/eight ==> CORRECT thirteen) five/7 / (two/7) = five/7 x 7/two = (five x 7) / (7 x two) = 35 / 14 14) two/three / (one million/four) = two/three x four = eight / three 15) one million/two / (two/nine) = one million/two x nine/two = nine / (two x two) = nine / four In a few circumstances, while now we have a fragment it's bigger if we write it as a decimal (with ease by means of dividing the numerator with the denominator). But in a few circumstances it is also a bigger inspiration to paintings best with the numerators of the fractions (if they've the equal denominator). Also, take into account that after dividing fractions you're honestly multiplying the fraction by means of the reciprocal of the opposite one. Example: two/nine divided by means ! of five/eight ==> two/nine / (five/eight) divided (/) by means! of five/eight ==> instances (x) eight/five (reciprocal of five/eight) two/nine / (five/eight) = two/nine x eight/five = (two x eight) / (nine x five) = sixteen / forty five NOTE: If the fraction will also be simplified, do it. In this example sixteen and forty five can not be simplified however they may be able to be provided as a decimal (sixteen/forty five = zero.35). Hope this helped and well good fortune! :)...Show more

Jill Thomer: [x5-x3+x2-1-(x3-1)(x+1)2]/[(x2-1)2]=[x^3(X^2-1)+(x^2-1)-(x-1)(x^2+x+1)(x+1)(x+1)]/[(x2-1)^2={(x^2-1)[x^3+1-(x^2+x+1)(x-1)}/[(x2-1)^2=[x^3+1-(x^3-x^2+x^2-x+x-1)]/(x^2-1)=[x^3+1-(x^3-1)]/(x^2-1)=[x^3+1-x^3+1]/(x^2-1)=2/(x^2-1)...Show more

Judie Kise: ✐Explanation✐[x^5 - x³ + x² - 1 - (x³ - 1)(x + 1)²]/(x² - 1)²Factor (x³ - 1)(x + 1)² and (x² - 1)².[x^5 - x³ + x² - 1 - x^5 - 2x^4 - x³ + 2x + 1]/(x^4 - 2x² + 1)Combine like terms for the polynomial in the numerator. You get:(-2x^4 - 2x³ + x² + 2x)/(x^4 - 2x² + 1! )I hope this helps!...Show more